计算 (-2ab)^2+(a^2-2b)^2-(a^2+b^2)(a^2-b^2) (3x-2)(x-3)-2(x-5)(x+6)-(x^2-7x+13),其中x=3又1/2
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![计算 (-2ab)^2+(a^2-2b)^2-(a^2+b^2)(a^2-b^2) (3x-2)(x-3)-2(x-5)(x+6)-(x^2-7x+13),其中x=3又1/2](/uploads/image/z/12651468-60-8.jpg?t=%E8%AE%A1%E7%AE%97+%28-2ab%29%5E2%2B%28a%5E2-2b%29%5E2-%28a%5E2%2Bb%5E2%29%28a%5E2-b%5E2%29+%283x-2%29%28x-3%29-2%28x-5%29%28x%2B6%29-%28x%5E2-7x%2B13%29%2C%E5%85%B6%E4%B8%ADx%3D3%E5%8F%881%2F2)
计算 (-2ab)^2+(a^2-2b)^2-(a^2+b^2)(a^2-b^2) (3x-2)(x-3)-2(x-5)(x+6)-(x^2-7x+13),其中x=3又1/2
计算 (-2ab)^2+(a^2-2b)^2-(a^2+b^2)(a^2-b^2) (3x-2)(x-3)-2(x-5)(x+6)-(x^2-7x+13),其中x=3又1/2
计算 (-2ab)^2+(a^2-2b)^2-(a^2+b^2)(a^2-b^2) (3x-2)(x-3)-2(x-5)(x+6)-(x^2-7x+13),其中x=3又1/2
(-2ab)^2+(a^2-2b)^2-(a^2+b^2)(a^2-b^2)
=4a^b^+a^4-4a^b^+4b^4-(a^4-b^4)
=5b^4.
(3x-2)(x-3)-2(x-5)(x+6)-(x^2-7x+13)
=3x^-11x+6-2(x^+x-30)-(x^2-7x+13)
=3x^-11x+6
-2x^-2x+60
-x^+7x-13
= -6x+53,
x=3又1/2时原式=-21+53=32.
看楼下的吧,他应该是对的,我验算了一遍。O(∩_∩)O哈!