已知tanX=1,在下列区间中求X(1) (-π/2,π/2)(2) (0,2π)
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![已知tanX=1,在下列区间中求X(1) (-π/2,π/2)(2) (0,2π)](/uploads/image/z/12607758-54-8.jpg?t=%E5%B7%B2%E7%9F%A5tanX%3D1%2C%E5%9C%A8%E4%B8%8B%E5%88%97%E5%8C%BA%E9%97%B4%E4%B8%AD%E6%B1%82X%EF%BC%881%EF%BC%89+%EF%BC%88-%CF%80%2F2%2C%CF%80%2F2%EF%BC%89%EF%BC%882%EF%BC%89+%EF%BC%880%2C2%CF%80%EF%BC%89)
已知tanX=1,在下列区间中求X(1) (-π/2,π/2)(2) (0,2π)
已知tanX=1,在下列区间中求X
(1) (-π/2,π/2)
(2) (0,2π)
已知tanX=1,在下列区间中求X(1) (-π/2,π/2)(2) (0,2π)
根据正弦函数图像性质,得到x的解集是x=kx+π/4.
(1)当k=0时,x满足情况,得x=π/4.
(2)当k=0,k=1时,x满足情况,得x=π/4和x=5π/4
π/4,
π/4,5/4