若a+β=π/4,求(1+tanα)(1+tanβ)的值
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若a+β=π/4,求(1+tanα)(1+tanβ)的值
若a+β=π/4,求(1+tanα)(1+tanβ)的值
若a+β=π/4,求(1+tanα)(1+tanβ)的值
tan(α+β)=(tanα+tanβ)/(1-tanαtanβ)=1
tanα+tanβ+tanαtanβ=1
(1+tanα)(1+tanβ)=1+tanαtanβ+tanα+tanβ=2