若(a+1)ˆ2+|b-2|=0,化简a(xˆ2y+xyˆ2)-b(xˆ2y-xyˆ2)=
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![若(a+1)ˆ2+|b-2|=0,化简a(xˆ2y+xyˆ2)-b(xˆ2y-xyˆ2)=](/uploads/image/z/12052569-57-9.jpg?t=%E8%8B%A5%EF%BC%88a%2B1%EF%BC%89%26%23710%3B2%2B%7Cb-2%7C%3D0%2C%E5%8C%96%E7%AE%80a%EF%BC%88x%26%23710%3B2y%2Bxy%26%23710%3B2%EF%BC%89-b%EF%BC%88x%26%23710%3B2y-xy%26%23710%3B2%EF%BC%89%3D)
若(a+1)ˆ2+|b-2|=0,化简a(xˆ2y+xyˆ2)-b(xˆ2y-xyˆ2)=
若(a+1)ˆ2+|b-2|=0,化简a(xˆ2y+xyˆ2)-b(xˆ2y-xyˆ2)=
若(a+1)ˆ2+|b-2|=0,化简a(xˆ2y+xyˆ2)-b(xˆ2y-xyˆ2)=
(a+1)ˆ2+|b-2|=0 得到a=-1 b=2
a(xˆ2y+xyˆ2)-b(xˆ2y-xyˆ2)
=-x^2y-xy^2-2x^2y+2xy^2
=-3x^2y+xy^2
=xy(-3x+y)