若多项式3x^4-(a+1)x³+(b-2)x²-2x+3不含x³项和x²的项,求ab(a+1)
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若多项式3x^4-(a+1)x³+(b-2)x²-2x+3不含x³项和x²的项,求ab(a+1)
若多项式3x^4-(a+1)x³+(b-2)x²-2x+3不含x³项和x²的项,
求ab(a+1)
若多项式3x^4-(a+1)x³+(b-2)x²-2x+3不含x³项和x²的项,求ab(a+1)
因为多项式3x^4-(a+1)x³+(b-2)x²-2x+3不含x³项和x²的项
所以-(a+1)=0,b-2=0
所以a=-1,b=2
ab(a+1)
=-1*2*0
=0