VB编程 s=5 for i=1 to 23step6 s=s+1 next i 执行程序,为啥i的值为25?
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![VB编程 s=5 for i=1 to 23step6 s=s+1 next i 执行程序,为啥i的值为25?](/uploads/image/z/11532656-56-6.jpg?t=VB%E7%BC%96%E7%A8%8B+s%3D5+for+i%3D1+to+23step6+s%3Ds%2B1+next+i+%E6%89%A7%E8%A1%8C%E7%A8%8B%E5%BA%8F%2C%E4%B8%BA%E5%95%A5i%E7%9A%84%E5%80%BC%E4%B8%BA25%3F)
VB编程 s=5 for i=1 to 23step6 s=s+1 next i 执行程序,为啥i的值为25?
VB编程 s=5 for i=1 to 23step6 s=s+1 next i 执行程序,为啥i的值为25?
VB编程 s=5 for i=1 to 23step6 s=s+1 next i 执行程序,为啥i的值为25?
当然啦
i=1,7,13,19,当再加一次步长就变成25,超出23,因此便跳出循环