(2012•盐城)如图所示,AC⊥AB,AB=2 根号3 ,AC=2,点D是以AB为直径的平面O上一动点,DE⊥CD交直(2012•盐城)如图所示,AC⊥AB,AB=2根号3 ,AC=2,点D是以AB为直径的平面O上一动点,DE⊥CD交直线AB于点
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![(2012•盐城)如图所示,AC⊥AB,AB=2 根号3 ,AC=2,点D是以AB为直径的平面O上一动点,DE⊥CD交直(2012•盐城)如图所示,AC⊥AB,AB=2根号3 ,AC=2,点D是以AB为直径的平面O上一动点,DE⊥CD交直线AB于点](/uploads/image/z/11411884-28-4.jpg?t=%EF%BC%882012%26%238226%3B%E7%9B%90%E5%9F%8E%EF%BC%89%E5%A6%82%E5%9B%BE%E6%89%80%E7%A4%BA%2CAC%E2%8A%A5AB%2CAB%3D2+%E6%A0%B9%E5%8F%B73+%2CAC%3D2%2C%E7%82%B9D%E6%98%AF%E4%BB%A5AB%E4%B8%BA%E7%9B%B4%E5%BE%84%E7%9A%84%E5%B9%B3%E9%9D%A2O%E4%B8%8A%E4%B8%80%E5%8A%A8%E7%82%B9%2CDE%E2%8A%A5CD%E4%BA%A4%E7%9B%B4%EF%BC%882012%26%238226%3B%E7%9B%90%E5%9F%8E%EF%BC%89%E5%A6%82%E5%9B%BE%E6%89%80%E7%A4%BA%2CAC%E2%8A%A5AB%2CAB%3D2%E6%A0%B9%E5%8F%B73+%2CAC%3D2%2C%E7%82%B9D%E6%98%AF%E4%BB%A5AB%E4%B8%BA%E7%9B%B4%E5%BE%84%E7%9A%84%E5%B9%B3%E9%9D%A2O%E4%B8%8A%E4%B8%80%E5%8A%A8%E7%82%B9%2CDE%E2%8A%A5CD%E4%BA%A4%E7%9B%B4%E7%BA%BFAB%E4%BA%8E%E7%82%B9)
(2012•盐城)如图所示,AC⊥AB,AB=2 根号3 ,AC=2,点D是以AB为直径的平面O上一动点,DE⊥CD交直(2012•盐城)如图所示,AC⊥AB,AB=2根号3 ,AC=2,点D是以AB为直径的平面O上一动点,DE⊥CD交直线AB于点
(2012•盐城)如图所示,AC⊥AB,AB=2 根号3 ,AC=2,点D是以AB为直径的平面O上一动点,DE⊥CD交直
(2012•盐城)如图所示,AC⊥AB,AB=2根号3 ,AC=2,点D是以AB为直径的平面O上一动点,DE⊥CD交直线AB于点E,设∠DAB=α(0°<α<90°).
(1)当α=18°时,求BD的长;
(2)当α=30°时,求线段BE的长;
(3)若要使点E在线段BA的延长线上,则α的取值范围是.(直接写出答案)
只要第三题就可以了,没有过程也可以
(2012•盐城)如图所示,AC⊥AB,AB=2 根号3 ,AC=2,点D是以AB为直径的平面O上一动点,DE⊥CD交直(2012•盐城)如图所示,AC⊥AB,AB=2根号3 ,AC=2,点D是以AB为直径的平面O上一动点,DE⊥CD交直线AB于点
(3)60°<α<90°