若(m^2+n^2)^2-4(m^2+n^2-1)=9,求m^2+n^2亲们~帮帮忙速度要快啊,
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若(m^2+n^2)^2-4(m^2+n^2-1)=9,求m^2+n^2亲们~帮帮忙速度要快啊,
若(m^2+n^2)^2-4(m^2+n^2-1)=9,求m^2+n^2
亲们~帮帮忙
速度要快啊,
若(m^2+n^2)^2-4(m^2+n^2-1)=9,求m^2+n^2亲们~帮帮忙速度要快啊,
(m^2+n^2)^2-4(m^2+n^2-1)=9,
令m^2+n^2=t,则原方程变为:
t^2-4(t-1)=9
t^2-4t-5=0
(t-5)(t+1)=0
t=5或t=-1(m^2+n^2≥0,舍去)
所以
m^2+n^2=5
[(m+n)(m-n)-(m-n)²+2n(m-n)]÷4n
(1),(-m-n)(-m+n) (2),(-m+n)(m-n)
(m-2n)(-m-n)
(n/m+n/2m^2)*4m/n^2
[(m-n)^2*(m-n)^3]^2/(m-n)^4
[(m-n)^2*(m-n)^3]^2/(m-n)^4
4m^2(m+n)-9n^2(m+n)
因式分解4m^2(m-n)+4n(n-m)
4m(m-n)^2+4n(n-m)^3
(m-n)2(n-m)3(n-m)4化简
化简,1.[(m+n-p)(m+p+n)-(m+n)²]/(-p),2.[(m+n)(m-n)-(m-n)²+2n(m-n)]/4n
(m-n)^2*(m-n)^4=?
m-n+2n^2/(m+n)
4m(m-m)-2n(n-m)
(m-2n/n-m)-(n/m-n)=
2(m-n)²-m(m-n)
(m-n)(m+n)+(m+n)²-2m²
已知3m=4n,则m/m+n+n/m-n-m^2/m^2-n^2=