函数(x)=log1/3(6-x-x^2)的单调递增区间是( )A [-1/2,+∞] B [-1/2,2]c(-∝,-1/2) D (-3,-1/2)
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![函数(x)=log1/3(6-x-x^2)的单调递增区间是( )A [-1/2,+∞] B [-1/2,2]c(-∝,-1/2) D (-3,-1/2)](/uploads/image/z/10769393-65-3.jpg?t=%E5%87%BD%E6%95%B0%28x%29%3Dlog1%EF%BC%8F3%EF%BC%886-x-x%5E2%29%E7%9A%84%E5%8D%95%E8%B0%83%E9%80%92%E5%A2%9E%E5%8C%BA%E9%97%B4%E6%98%AF%28+%29A+%5B-1%EF%BC%8F2%2C%2B%E2%88%9E%5D+B+%5B-1%EF%BC%8F2%2C2%5Dc%28%EF%BC%8D%E2%88%9D%2C-1%EF%BC%8F2%29+D+%28-3%2C-1%EF%BC%8F2%29)
函数(x)=log1/3(6-x-x^2)的单调递增区间是( )A [-1/2,+∞] B [-1/2,2]c(-∝,-1/2) D (-3,-1/2)
函数(x)=log1/3(6-x-x^2)的单调递增区间是( )A [-1/2,+∞] B [-1/2,2]
c(-∝,-1/2) D (-3,-1/2)
函数(x)=log1/3(6-x-x^2)的单调递增区间是( )A [-1/2,+∞] B [-1/2,2]c(-∝,-1/2) D (-3,-1/2)
先看定义域
x-x^2>0
x(x-1)<0
0<x<1
要求f(x)=log1/2(x-x^2)的单调递增区间
即求x-x^2的减区间
x-x^2=-(x^2-x)=-(x-1/2)^2+1/4
所以增区间是(0,1/2) 减区间是(1/2,1)
所以f(x)=log1/2(x-x*2)的单调递增区间为(1/2,1)