抛物线y=-x²+2bx+c的顶点(2,1)的b= a=
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 08:59:38
![抛物线y=-x²+2bx+c的顶点(2,1)的b= a=](/uploads/image/z/10760672-56-2.jpg?t=%E6%8A%9B%E7%89%A9%E7%BA%BFy%3D-x%26%23178%3B%2B2bx%2Bc%E7%9A%84%E9%A1%B6%E7%82%B9%282%2C1%29%E7%9A%84b%3D+a%3D)
抛物线y=-x²+2bx+c的顶点(2,1)的b= a=
抛物线y=-x²+2bx+c的顶点(2,1)的b= a=
抛物线y=-x²+2bx+c的顶点(2,1)的b= a=
y=-(x-b)^2+b^2+c
顶点为(b,b^2+c);
解方程b=2;
b^2+c=1;
得
b=2;c=-3
y=-(x-b)^2+b^2+c
顶点为(b,b^2+c);
解方程b=2;
b^2+c=1;
得
b=2;c=-3