VmL Al2(SO4)3 溶液中,含有Al3+ ag,取V/2mL溶液稀释到3VmL,则稀释后溶液中SO4 2-的浓度是()A.250a/27V mol/L B.250a/9V mol/L C.500a/9V mol/L D.125a/9V mol/L那个……下角标和上角标我打不出 凑合看吧……
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![VmL Al2(SO4)3 溶液中,含有Al3+ ag,取V/2mL溶液稀释到3VmL,则稀释后溶液中SO4 2-的浓度是()A.250a/27V mol/L B.250a/9V mol/L C.500a/9V mol/L D.125a/9V mol/L那个……下角标和上角标我打不出 凑合看吧……](/uploads/image/z/10754400-48-0.jpg?t=VmL+Al2%28SO4%293+%E6%BA%B6%E6%B6%B2%E4%B8%AD%2C%E5%90%AB%E6%9C%89Al3%2B+ag%2C%E5%8F%96V%2F2mL%E6%BA%B6%E6%B6%B2%E7%A8%80%E9%87%8A%E5%88%B03VmL%2C%E5%88%99%E7%A8%80%E9%87%8A%E5%90%8E%E6%BA%B6%E6%B6%B2%E4%B8%ADSO4+2-%E7%9A%84%E6%B5%93%E5%BA%A6%E6%98%AF%EF%BC%88%EF%BC%89A.250a%2F27V+mol%2FL+B.250a%2F9V+mol%2FL+C.500a%2F9V+mol%2FL+D.125a%2F9V+mol%2FL%E9%82%A3%E4%B8%AA%E2%80%A6%E2%80%A6%E4%B8%8B%E8%A7%92%E6%A0%87%E5%92%8C%E4%B8%8A%E8%A7%92%E6%A0%87%E6%88%91%E6%89%93%E4%B8%8D%E5%87%BA+%E5%87%91%E5%90%88%E7%9C%8B%E5%90%A7%E2%80%A6%E2%80%A6)
VmL Al2(SO4)3 溶液中,含有Al3+ ag,取V/2mL溶液稀释到3VmL,则稀释后溶液中SO4 2-的浓度是()A.250a/27V mol/L B.250a/9V mol/L C.500a/9V mol/L D.125a/9V mol/L那个……下角标和上角标我打不出 凑合看吧……
VmL Al2(SO4)3 溶液中,含有Al3+ ag,取V/2mL溶液稀释到3VmL,则稀释后溶液中SO4 2-的浓度是()
A.250a/27V mol/L B.250a/9V mol/L C.500a/9V mol/L D.125a/9V mol/L
那个……下角标和上角标我打不出 凑合看吧……
VmL Al2(SO4)3 溶液中,含有Al3+ ag,取V/2mL溶液稀释到3VmL,则稀释后溶液中SO4 2-的浓度是()A.250a/27V mol/L B.250a/9V mol/L C.500a/9V mol/L D.125a/9V mol/L那个……下角标和上角标我打不出 凑合看吧……
原溶液中Al3+的物质的量为:n(Al3+)=ag/27g/mol=a/27 mol
所以原溶液中 Al2(SO4)3的物质的量为n【 Al2(SO4)3】=a/54 mol
原溶液中Al2(SO4)3的量浓度为:
c【 Al2(SO4)3】=n【 Al2(SO4)3】/V=a/54/V=1000a/54V mol/L=500a/27V mol/L(这一步中有单位换算,要注意,是mL与L的换算)
原溶液中SO4 2-的量浓度为:
c(SO4 2-)=3×c【 Al2(SO4)3】=3×500a/27V =500a/9V mol/L
V/2 mL溶液稀释后SO4 2-的量浓度为:
c1=c(SO4 2-)×V/2 /3V=(500a/9V mol/L) × V/2 mL / 3V mL = 250a/27V mol/L
因为V/2mL溶液含有Al3+ a/2 g ,即n(Al3+) = m(Al3+)/M(Al)= a/2/27 = a/54 mol ,Al2(SO4)3中n(Al3+):n(SO4 2-) = 2:3 ,则n(SO4 2-) = 3* n(Al3+)/2 = a/36 mol ,所以c(SO4 2-) = n(SO4 2-)/V[Al2(SO4)3] = a/36/( 3V*10-3)= 9.2...
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因为V/2mL溶液含有Al3+ a/2 g ,即n(Al3+) = m(Al3+)/M(Al)= a/2/27 = a/54 mol ,Al2(SO4)3中n(Al3+):n(SO4 2-) = 2:3 ,则n(SO4 2-) = 3* n(Al3+)/2 = a/36 mol ,所以c(SO4 2-) = n(SO4 2-)/V[Al2(SO4)3] = a/36/( 3V*10-3)= 9.26a/ V
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