怎么求函数y=(x-2)³(3x+1)²的导数y'=3(x-2)²(3x+1)²+(x-2)³×2(3x+1)×3 y'=3(3x+1)(x-2)²(3x+1)+6(x-2)(x-2)²(3x+1) y'=(9x+3+6x-12)(x-2)²(3x+1) y'=3(5x-3)(3x+1)(x-2)²y'=3(x-2)²(3x+1)²+(x-2)
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![怎么求函数y=(x-2)³(3x+1)²的导数y'=3(x-2)²(3x+1)²+(x-2)³×2(3x+1)×3 y'=3(3x+1)(x-2)²(3x+1)+6(x-2)(x-2)²(3x+1) y'=(9x+3+6x-12)(x-2)²(3x+1) y'=3(5x-3)(3x+1)(x-2)²y'=3(x-2)²(3x+1)²+(x-2)](/uploads/image/z/1042640-8-0.jpg?t=%E6%80%8E%E4%B9%88%E6%B1%82%E5%87%BD%E6%95%B0y%3D%28x-2%29%26%23179%3B%283x%2B1%29%26%23178%3B%E7%9A%84%E5%AF%BC%E6%95%B0y%27%3D3%28x-2%29%26%23178%3B%283x%2B1%29%26%23178%3B%2B%28x-2%29%26%23179%3B%C3%972%283x%2B1%29%C3%973+y%27%3D3%283x%2B1%29%28x-2%29%26%23178%3B%283x%2B1%29%2B6%28x-2%29%28x-2%29%26%23178%3B%283x%2B1%29+y%27%3D%289x%2B3%2B6x-12%29%28x-2%29%26%23178%3B%283x%2B1%29+y%27%3D3%285x-3%29%283x%2B1%29%28x-2%29%26%23178%3By%27%3D3%28x-2%29%26%23178%3B%283x%2B1%29%26%23178%3B%2B%28x-2%29%26%2317)
怎么求函数y=(x-2)³(3x+1)²的导数y'=3(x-2)²(3x+1)²+(x-2)³×2(3x+1)×3 y'=3(3x+1)(x-2)²(3x+1)+6(x-2)(x-2)²(3x+1) y'=(9x+3+6x-12)(x-2)²(3x+1) y'=3(5x-3)(3x+1)(x-2)²y'=3(x-2)²(3x+1)²+(x-2)
怎么求函数y=(x-2)³(3x+1)²的导数
y'=3(x-2)²(3x+1)²+(x-2)³×2(3x+1)×3
y'=3(3x+1)(x-2)²(3x+1)+6(x-2)(x-2)²(3x+1)
y'=(9x+3+6x-12)(x-2)²(3x+1)
y'=3(5x-3)(3x+1)(x-2)²
y'=3(x-2)²(3x+1)²+(x-2)³×2(3x+1)×3
最后这个三,不是跟整个前面的式子.3(x-2)²(3x+1)²+(x-2)³×2(3x+1)
这个乘么.为什么只是跟最后一个式子乘呢,
怎么求函数y=(x-2)³(3x+1)²的导数y'=3(x-2)²(3x+1)²+(x-2)³×2(3x+1)×3 y'=3(3x+1)(x-2)²(3x+1)+6(x-2)(x-2)²(3x+1) y'=(9x+3+6x-12)(x-2)²(3x+1) y'=3(5x-3)(3x+1)(x-2)²y'=3(x-2)²(3x+1)²+(x-2)
y导数是两项之和
第一项为(x-2)³的导数乘(3x+1)²,第二项为(x-2)³乘(3x+1)²的导数,
(3x+1)²的导数是2(3x+1)*3
所以3只是跟最后一个式子乘
最后一个3是对(3x+1)求导而得到的,放在最后是对的。
乘法 前导后不导+后导前不导
带次数 应采用复合函数