若a1,a2,b1,b2满足a1²+b1²=1,a2²+b2²=1,且a1a2+b1b2=0求证:a1²+a2²=1,b1²+b2²=1,且a1b1+a2b2=0请用一个正常学生能看懂的思路解答
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 03:20:29
![若a1,a2,b1,b2满足a1²+b1²=1,a2²+b2²=1,且a1a2+b1b2=0求证:a1²+a2²=1,b1²+b2²=1,且a1b1+a2b2=0请用一个正常学生能看懂的思路解答](/uploads/image/z/10285966-46-6.jpg?t=%E8%8B%A5a1%2Ca2%2Cb1%2Cb2%E6%BB%A1%E8%B6%B3a1%26%23178%3B%2Bb1%26%23178%3B%3D1%2Ca2%26%23178%3B%2Bb2%26%23178%3B%3D1%2C%E4%B8%94a1a2%2Bb1b2%3D0%E6%B1%82%E8%AF%81%EF%BC%9Aa1%26%23178%3B%2Ba2%26%23178%3B%3D1%2Cb1%26%23178%3B%2Bb2%26%23178%3B%3D1%2C%E4%B8%94a1b1%2Ba2b2%3D0%E8%AF%B7%E7%94%A8%E4%B8%80%E4%B8%AA%E6%AD%A3%E5%B8%B8%E5%AD%A6%E7%94%9F%E8%83%BD%E7%9C%8B%E6%87%82%E7%9A%84%E6%80%9D%E8%B7%AF%E8%A7%A3%E7%AD%94)
若a1,a2,b1,b2满足a1²+b1²=1,a2²+b2²=1,且a1a2+b1b2=0求证:a1²+a2²=1,b1²+b2²=1,且a1b1+a2b2=0请用一个正常学生能看懂的思路解答
若a1,a2,b1,b2满足a1²+b1²=1,a2²+b2²=1,且a1a2+b1b2=0
求证:a1²+a2²=1,b1²+b2²=1,且a1b1+a2b2=0
请用一个正常学生能看懂的思路解答
若a1,a2,b1,b2满足a1²+b1²=1,a2²+b2²=1,且a1a2+b1b2=0求证:a1²+a2²=1,b1²+b2²=1,且a1b1+a2b2=0请用一个正常学生能看懂的思路解答
设向量OA=(a1,b1) OB=(a2.b2)
a1^2+b1^2=1
a2^2+b2^2=1
就是说他们的模长为一
a1a2+b1b2=0
就是说他们互相垂直
(a1^2-a2^2)+(b1^2-b2^2)=0
所以就是说
a1^2-a2^2=0
b1^2-b2^2=0
所以咯
a1^2=a2^2
b1^2=b2^2
因为a1^2+a2^2=1,b1^2+b2^2=1
可以分别算出四个数,代进去算就可以了
大概就是这样了!