△ABC的三边a,b,c满足a²-10a+c²-26c+194+√(2/3b-8)=0,试求a,b,c的值,并判断△ABC的形状.急!快快快!在线等!
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![△ABC的三边a,b,c满足a²-10a+c²-26c+194+√(2/3b-8)=0,试求a,b,c的值,并判断△ABC的形状.急!快快快!在线等!](/uploads/image/z/10260618-42-8.jpg?t=%E2%96%B3ABC%E7%9A%84%E4%B8%89%E8%BE%B9a%2Cb%2Cc%E6%BB%A1%E8%B6%B3a%26%23178%3B%EF%BC%8D10a%EF%BC%8Bc%26%23178%3B%EF%BC%8D26c%EF%BC%8B194%EF%BC%8B%E2%88%9A%282%EF%BC%8F3b%EF%BC%8D8%29%3D0%2C%E8%AF%95%E6%B1%82a%2Cb%2Cc%E7%9A%84%E5%80%BC%2C%E5%B9%B6%E5%88%A4%E6%96%AD%E2%96%B3ABC%E7%9A%84%E5%BD%A2%E7%8A%B6.%E6%80%A5%21%E5%BF%AB%E5%BF%AB%E5%BF%AB%21%E5%9C%A8%E7%BA%BF%E7%AD%89%21)
△ABC的三边a,b,c满足a²-10a+c²-26c+194+√(2/3b-8)=0,试求a,b,c的值,并判断△ABC的形状.急!快快快!在线等!
△ABC的三边a,b,c满足a²-10a+c²-26c+194+√(2/3b-8)=0,试求a,b,c的值,
并判断△ABC的形状.急!快快快!在线等!
△ABC的三边a,b,c满足a²-10a+c²-26c+194+√(2/3b-8)=0,试求a,b,c的值,并判断△ABC的形状.急!快快快!在线等!
a²-10a+c²-26c+194+√(2/3b-8)=0
(a-5)²+(c-13)²+√(2b/3-8)=0;
∴a-5=0;
a=5;
c-13=0;
c=13;
2b/3=8;
b=12;
所以a²+b²=c²;
所以是直角三角形
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