Given any 10 different positive integers less than 100.there will be two disjoint subsets with the same sum.举个例子我任意给出10个:44,54,84,24,14,95,67,59,35,48。这10个数的集合里会有2个不相交的子集,他
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![Given any 10 different positive integers less than 100.there will be two disjoint subsets with the same sum.举个例子我任意给出10个:44,54,84,24,14,95,67,59,35,48。这10个数的集合里会有2个不相交的子集,他](/uploads/image/z/10214952-24-2.jpg?t=Given+any+10+different+positive+integers+less+than+100.there+will+be+two+disjoint+subsets+with+the+same+sum.%E4%B8%BE%E4%B8%AA%E4%BE%8B%E5%AD%90%E6%88%91%E4%BB%BB%E6%84%8F%E7%BB%99%E5%87%BA10%E4%B8%AA%EF%BC%9A44%EF%BC%8C54%EF%BC%8C84%EF%BC%8C24%EF%BC%8C14%EF%BC%8C95%EF%BC%8C67%EF%BC%8C59%EF%BC%8C35%EF%BC%8C48%E3%80%82%E8%BF%9910%E4%B8%AA%E6%95%B0%E7%9A%84%E9%9B%86%E5%90%88%E9%87%8C%E4%BC%9A%E6%9C%892%E4%B8%AA%E4%B8%8D%E7%9B%B8%E4%BA%A4%E7%9A%84%E5%AD%90%E9%9B%86%EF%BC%8C%E4%BB%96)
Given any 10 different positive integers less than 100.there will be two disjoint subsets with the same sum.举个例子我任意给出10个:44,54,84,24,14,95,67,59,35,48。这10个数的集合里会有2个不相交的子集,他
Given any 10 different positive integers less than 100.there will be two disjoint subsets with the same sum.
举个例子我任意给出10个:44,54,84,24,14,95,67,59,35,48。这10个数的集合里会有2个不相交的子集,他们的和相同比如44,24和54,14。这个是证明题
Given any 10 different positive integers less than 100.there will be two disjoint subsets with the same sum.举个例子我任意给出10个:44,54,84,24,14,95,67,59,35,48。这10个数的集合里会有2个不相交的子集,他
给定任意10个小于100的正整数.会有两个不相交的子集有相同的和.(感觉逻辑不大通.这两句话本来就是连在一道的么?还是当中有省略的部分呀)如32,42,62,22,12,67,56,33,41
32,42,62,22,12,67,56,33,41。
给定任意10个小于100的正整数。会有两个不相交的子集有相同的和。(感觉逻辑不大通。这两句话本来就是连在一道的么?还是当中有省略的部分呀)
打电话问老师吧(老师很喜欢爱提问的学生哟)O(∩_∩)O哈哈~