a+19=b+9=c+8则(a-b)^2+(b-c)^2+(c-a)^2=多少
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 20:22:36
![a+19=b+9=c+8则(a-b)^2+(b-c)^2+(c-a)^2=多少](/uploads/image/z/10146884-68-4.jpg?t=a%2B19%3Db%2B9%3Dc%2B8%E5%88%99%EF%BC%88a-b%EF%BC%89%5E2%2B%28b-c%29%5E2%2B%28c-a%29%5E2%3D%E5%A4%9A%E5%B0%91)
a+19=b+9=c+8则(a-b)^2+(b-c)^2+(c-a)^2=多少
a+19=b+9=c+8则(a-b)^2+(b-c)^2+(c-a)^2=多少
a+19=b+9=c+8则(a-b)^2+(b-c)^2+(c-a)^2=多少
a+19=b+9=c+8则a-b=-10,b-c=-1,c-a=11
带入计算即可
a-b=-10
b-c=-1
c-a=11
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